Two liquids 'A' (molecular mass =20) and 'B' (molecular mass =40) are partially miscible. When 1 mol of A, 3 mol of B are shaken together and allowed to settle, two layer 'M' and 'N' are formed as shown in diagram. Layer 'M' contains 0.2 mole fraction of 'A' and layer 'N' contain 0.6 mole fraction of A. Calculate the ratio of masses of layer M to layer N.

Two liquids 'A' (molecular mass =20) and 'B' (molecular mass =40) are

1.	Two liquids 'A' (molecular mass =20) and 'B' (molecular mass =40) are partially miscible. When 1 mol of A, 3 mol of B are shaken together and allowed to settle, two layer 'M' and 'N' are formed as shown in diagram. Layer 'M' contains 0.2 mole fraction of 'A' and layer 'N' contain 0.6 mole fraction of A. Calculate the ratio of masses of layer M to layer N.
Answer» SOLUTION :In layer `M` `n_(A)=x n_(B)=y` `x/(x+y)=0.2impliesy/x+1=5impliesy/x=4impliesy=4x` In layer `N` LTBR. `((i-x))/((1-x)(3-y))=0.6` `(3-y)/(1-x)+1=1/0.6implies(3-y)/(1-x)=4/6=2/3` `=9-3y=2-2x` `7=10ximpliesx=0.7, y=2.8` `w_(M)=0.7xx20+0.7xx4xx40=14+7xx16=126` `w_(N)=0.3xx20+0.2xx40=14` `w_(M)//w_(N)=9`