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Two long, parallel conductors carry currents in the same direction, as shown in figure. Conductors A held firmly in position. Conductors B carries a current `I_(B)` and is allowed to slide freely up and down (parallel to A) between a se of non-conducting guides. the mass per unit length of conductors B is 0.1 g/cm and the distance between the two conductors is 5 cm. if system of conductors is in equilibrium , the value of current `I_(B)` is A. 250 AB. 240 AC. 220 AD. 230 A |
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Answer» Correct Answer - a When system of conductors is in equilibrium. The magnetic force of attraction per unit length between conductors =weight of conductors B per unit length. `(mu_(0))/(2pi) (l_(A)xxl_(B))/d=(mg)/L =(m/L)g` `(mu_(0))/(2pi) (l_(A)xxl_(B))/d=(m/L)g` `2xx10^(-7) xx(100xxl_(B))/0.05 =(0.01kg//m) xx10` |
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