Two long straight parallel wires carry charges `lambda_(1) and lamba_(2)` per unit length. The distance between them is d. Calculate the magnitude of force externed on the length of one due to charge on the other.

Two long straight parallel wires carry charges `lambda_(1) and lamba_(

1.	Two long straight parallel wires carry charges `lambda_(1) and lamba_(2)` per unit length. The distance between them is d. Calculate the magnitude of force externed on the length of one due to charge on the other.
Answer» Correct Answer - `(lambda_(1) lambda_(2))/(2pi in_(0) d)` Field intensity at the location of wire 2 due to charge on wire 1 is `E = lambda_(1)//2 pi in_(0) d` Charge on unit length of wire `2 , q = lambda_(2)` `:.` Force on unit length of wire 2, `f = qE = lambda_(2). (lambda_(1))/(2 pi in_(0)d) = (lambda_(1) lambda_(2))/(2pi in_(0) d)`

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Two long straight parallel wires carry charges `lambda_(1) and lamba_(2)` per unit length. The distance between them is d. Calculate the magnitude of force externed on the length of one due to charge on the other.

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