Two long strings `A` and B`, each having linear mass density `1.2 xx 10^(-2)kg//m` are stretched by different tensions `4.8 N` and `7.5N` respectively and are kept parallel to each other with their left ends at `x = 0`. Wave pulse are produced on the string at the left ends at `t = 0` on string `A` and at `t=20ms` on string `B`. When and where will the pulse on `B` overtake that on `A`?

Two long strings `A` and B`, each having linear mass density `1.2 xx 1

1.	Two long strings `A` and B`, each having linear mass density `1.2 xx 10^(-2)kg//m` are stretched by different tensions `4.8 N` and `7.5N` respectively and are kept parallel to each other with their left ends at `x = 0`. Wave pulse are produced on the string at the left ends at `t = 0` on string `A` and at `t=20ms` on string `B`. When and where will the pulse on `B` overtake that on `A`?
Answer» Correct Answer - A::B `v_(1) =sqrt((T)/(mu_(1))` `=sqrt((4.8)/(1.2 xx 10^(-2))) = 20 m//s` `v_(2) = sqrt(T_(2)/(mu_(2))) = sqrt((7.5)/(1.2 xx 10^(-2))` `=25m//s` Pulse will meet when `x_(A) =x_(B)` or `20t = 25(t -0.02)` `:. t =0.1s` and `x_(A)` or `x_(B) = 20 xx0.1 =2m`

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