InterviewSolution
Saved Bookmarks
| 1. |
Two masses each equal to m are lying on x-axis at `(-a,0)(+a,0)` respectively as shown in figure They are connected by a light string A force F is applied at the origin along vertical direction As a result the masses move toward each other without loosing contact with ground What is the acceleration of each mass? Assume the instantanceous position of the masses as`(-x,0)`and `(x,0)`A. `(F)/(m) (sqrt(a^(2)-x^(2)))/(x)`B. `(Fx)/(2msqrt(a^(2)-x^(2)))`C. `(F)/(m) (x)/(sqrt(a^(2)-x^(2)))`D. `(F)/(m)sqrt((a^(2)-x^(2))/(x))` |
|
Answer» Correct Answer - b |
|