Two masses m_1 = 5 kg and m_2= 4 kg tied to a string are hanging over a light frictionless pulley. What is the acceleration of each mass when left free to move? (g =9.8ms^(2))

Two masses m_1 = 5 kg and m_2= 4 kg tied to a string are hanging over

1.	Two masses m_1 = 5 kg and m_2= 4 kg tied to a string are hanging over a light frictionless pulley. What is the acceleration of each mass when left free to move? (g =9.8ms^(2))
Answer» Solution :`a = (m_1- m_2)/(m_1 + m_2) XX G = (5-4)/(5 +4) xx 10= 1/9 xx 10 = 1.1 ms^(-2)`