Two masses m_(1) and m_(2) are attached to a spring balance S as shown in Figure. If m_(1)gt m_(2) then the reading of spring balance will be

Two masses m_(1) and m_(2) are attached to a spring balance S as shown

1.	Two masses m_(1) and m_(2) are attached to a spring balance S as shown in Figure. If m_(1)gt m_(2) then the reading of spring balance will be
Answer» `(m_(1)-m_(2))` `(m_(1)+m_(2))` `(2m_(1)m_(2))/(m_(1)+m_(2))` `(m_(1)m_(2))/(m_(1)+m_(2))` Solution :`F_("NET")=ma, " FromFBD of "m_(1), m_(1)g-T_(1)=m_(1)a` From FBD of `m_(2), T_(2)-m_(2)g=m_(2)a` TAKE `T_(2)=T_(2)`, solving the above eq.s, we get .a.