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Two masses `m_1` and `m_2` are attached to the ends of a massless string which passes over a frictionless pulley attached to the top of an inclined plane. The angle of inclination of the plane is `theta`. Take `g=10ms^(-2)` if `m_(1)=10 kg,m_(2)=5 kg , theta=30^(@)`, what is the acceleration of mass `m_(2)`?A. zeroB. `(2//3)ms^(-2)`C. `5 ms^(-2)`D. `10//3 ms^(-2)` |
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Answer» Correct Answer - A `a=((m_(2)-m_(1) sin alpha)g)/((m_(1)+m_(2)))=((5-10 sin 30^(@))g)/((m_(1)+m_(2)))=0` |
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