InterviewSolution
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InterviewSolution
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Two masses (m_1) and (m_2) are suspended together by a massless spring of spring constant (k). When the masses are in equilibrium, (m_1) is removed without disturbing the system. Find the angular frequency and amplitude of oscillation of (m_2). . |
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Answer» Correct Answer - A::B. When masss (m_(1)) is removed then equilibrum will get disturbed. There will be a restoring forec is the upward direction. The body will undergo S.H.M. now. Let x_(1) be the extension of the spring when (m_(1)_m_(2)) are suspended and x_(2) be the extension of the sppring when `m_(1)` is remved. :. `kx_(1) =(m_(1)+m_(2))g or `(x_91) =(m_(1)+_(m2))g` and `kx_(2) =m_(2)g` or `x_(2) =(m_(2)g)/k` Amplitude of mean position. Restoring force will be or `A =((m_(1_+m_(2))g-m_(2)g)/k =(m_(1))/k` Let at any instant the mass `m_(2)` be having a displacement x from the mean position. Restoring force will be `F=-kx` or `m_(2)a=-kx` rArr `a k/(m_(2)x` Comparing this with `a=-omega^(2)x`, we get `omega^(2)=k/(m^(2) rArr omega=sqrtk/m_(2)`. |
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