Two masses M_(1) and M_(2) connected by means of a string which is made to pass over light, smooth pulley are in equilibrium on a fixed smooth wedge as shown in figure. If theta = 60^(@) and alpha = 30^(@), then the ratio of M_(1) to M_(2) is

Two masses M_(1) and M_(2) connected by means of a string which is mad

1.	Two masses M_(1) and M_(2) connected by means of a string which is made to pass over light, smooth pulley are in equilibrium on a fixed smooth wedge as shown in figure. If theta = 60^(@) and alpha = 30^(@), then the ratio of M_(1) to M_(2) is
Answer» `1:2` `2:SQRT3` `1:sqrt3` `sqrt3:1` SOLUTION :`m_(1)G sin theta=m_(2)g sin ALPHA`