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Two masses `M_(1)` and `M_(2)` connected by means of a string which is made to pass over light, smooth pulley are in equilibrium on a fixed smooth wedge as shown in figure. If `theta =60^(@)` and `alpha =30^(@)` then the ratio of `M_(1)` to `M_(2)` is .A. `1:2`B. `2:sqrt3`C. `1:sqrt3`D. `sqrt3:1` |
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Answer» Correct Answer - C `m_(1)g sin theta = m_(2) g sin alpha` |
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