Two masses m_(1)kg and m_(2)kg passes over a pulley. Find the ratio of the masses m_(1) and m_(2) so that string passes over the pulley will just start slipping over is surface. The friction coefficient between the string and pulley surface is 0.2

Two masses m_(1)kg and m_(2)kg passes over a pulley. Find the ratio of

1.	Two masses m_(1)kg and m_(2)kg passes over a pulley. Find the ratio of the masses m_(1) and m_(2) so that string passes over the pulley will just start slipping over is surface. The friction coefficient between the string and pulley surface is 0.2
Answer» Solution :From the ideas of laws of motion, for the TWO masses, `m_(1)g-T_(1)=M_(1)a........(1)` and `T_(2)-m_(2)g=m_(2)a.......(2)` and if string STARTS slipping we have `T_(1)=T_(2)e^(mupi)` SOLVING the above equations `m_(1)(g-a)=m_(2)(g+a)e^(mupi)` if string just slipps we can use a=0, THUS we have `m_(1)/m_(2)=e^(0.2pi)`