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Two masses `m` and `M` are attached with strings as shown. For the system to be in equilibrium we have. A. `tantheta=1+(2M)/(m)`B. `tantheta=1+(2m)/(M)`C. `tantheta=1+(M)/(2m)`D. `tantheta=1+(m)/(2M)` |
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Answer» Correct Answer - A For the smooth upper half, (2l= length of incline) `v^(2)-u^(2)=2aS` `v^(2)-0=2gsin theta l` `v=sqrt(2gsin thetal)` For the lower half, `v^(2)-u^(2)=2aS` `0-2g sin theta l =- 2g(mucos theta-sin theta)l` `sintheta=mucos theta-sintheta` `mu=2tan theta` |
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