Two masses m, and m, moving with velocities v_a and v_b in opposite direction collide elastically and after the collision m_a and m_b move with velocities v_b and v_a respectively. Then the ratio (m_a)/(m_b) is

Two masses m, and m, moving with velocities v_a and v_b in opposite di

1.	Two masses m, and m, moving with velocities v_a and v_b in opposite direction collide elastically and after the collision m_a and m_b move with velocities v_b and v_a respectively. Then the ratio (m_a)/(m_b) is
Answer» `((v_a - v_b)/(v_a + v_b))` `(v_a + v_b)/(v_a + v_b)` `1` `1/2` SOLUTION :As VELOCITIES are exchanged on PERFECTLY elastic collision , therefore , masses of TWO objects must be equal. `:. (m_a)/(m_b) = 1 " or " m_a = m_b`