Two masses ma and rnb moving with velocitics va and vb in opposite d

1.	Two masses ma and rnb moving with velocitics va and vb in opposite direction collide elastically and after the collision ma and mb move with velocities vb and va respectively.Then the ratio mamb is(A) \(\frac{v_a-v_b}{v_a+v_b}\)(B) \(\frac{m_a+m_b}{m_a}\)(C) 1(D) \(\frac{1}{2}\)
Answer» Correct option is: (C) 1 \(\overrightarrow F_{net} = 0\) \(\frac{\overrightarrow {dp}}{dt} = 0\) \(m_A \ v_A + m_B v_B = m_B v_A + m_A \ v_B\) \(m_A \ v_A - m_B \ v_B = -m_B \ v_A + m_A \ v_B\) \(m_A(v_A + v_B) = m_B (v_A + v_B)\) \(\frac{m_A}{m_B} = 1\) Correct option is: (C) 1

Two masses ma and rnb moving with velocitics va and vb in opposite direction collide elastically and after the collision ma and mb move with velocities vb and va respectively.Then the ratio mamb is(A) \(\frac{v_a-v_b}{v_a+v_b}\)(B) \(\frac{m_a+m_b}{m_a}\)(C) 1(D) \(\frac{1}{2}\)

Answer»

Correct option is: (C) 1

\(\overrightarrow F_{net} = 0\)

\(\frac{\overrightarrow {dp}}{dt} = 0\)

\(m_A \ v_A + m_B v_B = m_B v_A + m_A \ v_B\)

\(m_A \ v_A - m_B \ v_B = -m_B \ v_A + m_A \ v_B\)

\(m_A(v_A + v_B) = m_B (v_A + v_B)\)

\(\frac{m_A}{m_B} = 1\)

Correct option is: (C) 1