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Two masses of 5 kg and 3 kg are suppended with help of massless inextensible strings as shown in Calculate T_(1) and T_(2) when whole system is going upwards with acceleration =2ms^(2) (us g= 9.8ms^(-2)) . |
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Answer» Solution :Here, `m_(1) = 5kg` `m_(2) = 3KG` ` G = 9.8 m//s^(2)` `a = 2 m//s^(2), ` UPWARDS `T_(1) = (m_(1) +m_(2)) (g +a) = (5+3) (9.8+2) = 94.4 N` ` T_(2) =m_(2) (g +a) = 3 (9.8 +2 ) = 35.4 N ` . |
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