Two masses of 5 kg and 3 kg are suspended with the help of massless in

1.	Two masses of 5 kg and 3 kg are suspended with the help of massless inextensible strings as shown in Fig. Calculate T1 and T2 when whole system is going upward with acceleration = 2 ms2 (use g = 9.8 ms-2).
Answer» m₁ = 5 kg, m₂ = 3 kg, g = 9.8 m/s² Force on mass m₁, T₁ − T₂ − m₁g = m₁a T₁ − T₂ − 5g = 5a T₁ − T₂ = 59.0 N Force on mass m₂ T₂ − m₂g = m₂a T₂ = m₂ (g + a) = 3(9.8+2) T₂ = 35.4 T₁ = T₂ + 59.0 or T₁ = 35.4 + 59.0 = 94.4 N

Two masses of 5 kg and 3 kg are suspended with the help of massless inextensible strings as shown in Fig. Calculate T1 and T2 when whole system is going upward with acceleration = 2 ms2 (use g = 9.8 ms-2).

Answer»

m₁ = 5 kg, m₂ = 3 kg, g = 9.8 m/s²

Force on mass m₁,

T₁ − T₂ − m₁g = m₁a

T₁ − T₂ − 5g = 5a

T₁ − T₂ = 59.0 N

Force on mass m₂

T₂ − m₂g = m₂a

T₂ = m₂ (g + a)

= 3(9.8+2)

T₂ = 35.4

T₁ = T₂ + 59.0

or T₁ = 35.4 + 59.0

= 94.4 N