InterviewSolution
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InterviewSolution
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Two mercury drops (each of radius r) merge to form a bigger drop. The surface energy of the bigger drop, if `T` is the surface tension isA. `2^(5//3)pir^(2)`B. `4pir^(2)T`C. `2pir^(2)T`D. `2^(8//3)pir^(2)` |
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Answer» Correct Answer - D Let `R` be the radius of the bigger drop, then volume of bigger drop `=2xx` volume of small drop `(4)/(3)piR^(3)=2xx(4)/(3)pir^(3),R=2^(1//3)`r Surface energy of bigger drop `E=4piR^(2)T=4xx2^(2//3)pir^(2)T=2^(8//3)pir^(2)T` |
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