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Two metallic conducors have net charge of `+70 pC and -70 pC`, which result in a potential difference of `20 V` between them. What is the capacitanace of the system ? |
Answer» Correct Answer - `3.5 pF` Here, `q = 70 pC = 70xx^(-12)C, V = 20 V`, `C = (q)/(V) = (70xx10^(-12))/(20) = 3.5xx10^(-12) F = 3.5 pF` |
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