InterviewSolution
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InterviewSolution
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Two metallic s pheres of radii `R_(1)` and `R_(2)` are connected b y a thin wire. If `+q_(1)~ and `+q_(2)` are the charges on the two s pheres thenA. `q_(1)// q_(2)=R_(1)^(2)//R_(2)^(2)`B. `q_(1)//q_(2)=R_(1)//R_(2)`C. `q_(1)//q _(2)=R_(1)^(3)//R_(2) ^(3)`D. `q_(1)//q_(2)=(R_(1)^(2)-R_(2)^(2))//(R_(1)^(2)+R_(2)^(2))` |
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Answer» Correct Answer - 2 When the two metallic spheres are connected by a wire, they are at the saem potential for a spherical conductor capacitiy `C=4piepsilon_(0)R`. ltbr. `therefore` Potential `V=("charge")/("capacity")` `therefore V_(1)=V_(2)` or `(q_(1))/(4pi epsilon_(0)R_(1))=(q_(2))/(4piepsilon_(0)R_(2))` `therefore (q_(1))/(q_( 2))=(R_(1))/(R_(2))` |
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