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Two metallic spheres of radii `R and 2 R` are charged so that both of these have same surface charge density, `sigma` . If they are connected to each other with a conducting wire, in which direction will the charge flow and why ? |
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Answer» Let `R_(1) = R, R_(2) = 2R`. If `Q_(1) and Q_(2)` are the respective charges, then as `sigma = (Q_(1))/(4pi R_(1)^(2)) = (Q_(2))/(4pi R_(2)^(2))` `:. (Q_(1))/(Q_(2)) = (R_(1)^(2))/(R_(2)^(2)) = ((R )/(2R))^(2) = (1)/(4)` `As V_(1) = (Q_(1))/(4pi in_(0) R_(1)) , V_(2) = (Q_(2))/(4pi in_(0) R_(2))` `:. (V_(1))/(V_(2)) = (Q_(1))/(Q_(2)) , (R_(2))/(R_(1)) = (1)/(4) xx (2)/(1) = (1)/(2)` Clearly, `V_(2) gt V_(1)`. Hence charge flows from sphere of radius `2 R` to sphere of radius R. |
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