1.

Two metallic spheres 'P' and 'Q' weighing 200 gwt and 150 gwt, respectively, balance each other when immersed in water. If the relative density of 'P' is 2 find the specific gravity of 'Q'.

Answer»

Solution :Weight of P in air, `W_(1p)=200 gwt`
Let weight of P in water be `W_(2p)`
`therefore` the apparent loss of weight of 'P' in water `=W_(1p)-W_(2p)`
`therefore` the relative DENSITY of 'P' `(W_(1p))/(W_(1p)-W_(2p))=2` (given)
`therefore (200)/(200-W_(2p))=2 implies W_(2p)`
`=200(1-(1)/(2))=100g _(WT)`
Weight of 'Q' in ARI, `W_(1q)=150` gwt
Let weight of 'Q' in water be `W_(2p)`
`therefore` the apparent loss of weight of 'Q' in water
`=W_(1p)-W_(2p)=150-W_(2q)`
But `W_(2p)=W_(2q)`
`therefore` apparent loss of weight of 'Q' in water
=150-100=50 gwt
`therefore` the specific gravity of `Q=(W_(1q))/(W_(1q)-W_(2q))=(150)/(50)=3`


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