Two metals A and B have E∘=−0.76 and +0.80 V, respectively. Which

1.	Two metals A and B have E∘=−0.76 and +0.80 V, respectively. Which will liberate H2 from H2SO4 ? Given, For A ; An++ne−→A E∘=−0.76 V For B ; Bn++ne−→B E∘=+0.80 V
Answer» Two metals A and B have $E^{\circ} = - 0.76$ and $+ 0.80 V$ , respectively. Which will liberate $H_{2}$ from $H_{2} S O_{4}$ ? Given, For A ; $A^{n +} + n e^{-} \to A$ $E^{\circ} = - 0.76 V$ For B ; $B^{n +} + n e^{-} \to B$ $E^{\circ} = + 0.80 V$

Two metals A and B have E∘=−0.76 and +0.80 V, respectively. Which will liberate H2 from H2SO4 ? Given, For A ; An++ne−→A E∘=−0.76 V For B ; Bn++ne−→B E∘=+0.80 V

Answer»

Two metals A and B have $E^{\circ} = - 0.76$ and $+ 0.80 V$ , respectively. Which will liberate $H_{2}$ from $H_{2} S O_{4}$ ?

Given,

For A ; $A^{n +} + n e^{-} \to A$
$E^{\circ} = - 0.76 V$
For B ; $B^{n +} + n e^{-} \to B$
$E^{\circ} = + 0.80 V$