Two metals M_(1) and M_(2) have reduction potential values of -xV and – InterviewSolution

InterviewSolution

1.	Two metals M_(1) and M_(2) have reduction potential values of -xV and +yV respectively. Which will liberate H_(2) in H_(2)SO_(4)?
Answer» Solution :METALS having negative REDUCTION potential ACTS as powerful reducing agent. SINCE `M_1` has `-xV,` therefore `M_1` having `+xV`, oxidation potential will liberate `H_2` from `H_2SO_4`.

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