Two minerals(X) and (Y)areconcentrated byflothfloatationprocess.Onroastingmineral (X)gavea shiningliquidmetal(Z )whilemineral(Y) undersimilarconditiongaveametaloxide (P) whichwasyellow whenhot and whilewhencold. Reduction of theoxide(P) withe cokegavemetal (Q).Identify the minerals(X) and (Y), the oxide(Z) and metals (P) and(Q).

Two minerals(X) and (Y)areconcentrated byflothfloatationprocess.Onroas

1.	Two minerals(X) and (Y)areconcentrated byflothfloatationprocess.Onroastingmineral (X)gavea shiningliquidmetal(Z )whilemineral(Y) undersimilarconditiongaveametaloxide (P) whichwasyellow whenhot and whilewhencold. Reduction of theoxide(P) withe cokegavemetal (Q).Identify the minerals(X) and (Y), the oxide(Z) and metals (P) and(Q).
Answer» Solution :(i) Sincethe minerals(X) and(Y) are concentrated by flothfloatation process, they must besulphideores. (ii) Sincethe SULPHIDE ore (X) onroastinggives thecorrespondingshiningliquid METAL (Z),THEREFORE, (Z) must beHg andthethe sulphidemineral (X)mustbecinnobar ,i.e.,HgS. `underset("Cinnabar(X)") ( 2 HgS)+3 O _ 2overset (Delta ) to2HgO+2 SO_ 2 ` `2 HgO+HgSoverset ( Delta ) tounderset ("Mercury(Z)")( 3Hg )+SO_ 2` (iii) Since thesulphidemineral (Y) onroasting gavean oxide (P) which was yellowwhen hotand whitewhen cold,therefore,metaloxide (P) must bezinc oxide (ZNO). FurthersinceZnO on reductionwithcokegavethemetal(Q),therefore, metal (Q) must be zinc (Zn) andthesulphidemineral (Y) mustbe zinceblende,ZnS. `underset ( "Zincblende (Y)") ( 2 Zn S)+3O_2overset (Delta ) to2 Z n O+2SO_ 2 ` `ZnO+Coverset (Delta )to underset ( "Zinc (Q)")(Zn) + CO` Thus,P=HgS, Y= ZnS, Z = Hg, P=ZnOand Q = Zn.