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InterviewSolution
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Two molecules of gas have speeds of `9 xx 10^(6) ms^(-1)` and `1 xx 10^(6) ms^(-1)` respectively. What is the root mean square speed of these molecules? |
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Answer» Here, `upsilon_(1) = 9 xx 10^(6)m//s^(-1) , upsilon_(2) = 1 xx 10^(6) ms^(-1)` `upsilon_(rms) = sqrt((upsilon_(1)^(2)+upsilon_(2)^(2))/(2)) = sqrt(((9xx10^(6))^(2)+(1xx10^(6))^(2))/(2)) = sqrt(41) xx 10^(6)m//s`. |
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