Two moles of a diatomic ideal gas is taken through a process PT = constant. Its temperature is increased from T_0 to 2T_0. Find the work done by the system?

Two moles of a diatomic ideal gas is taken through a process PT = cons

1.	Two moles of a diatomic ideal gas is taken through a process PT = constant. Its temperature is increased from T_0 to 2T_0. Find the work done by the system?
Answer» Solution :`W=int PdV` Here ` Pt =P_1 T_1=P_2 T_2=` constant`.C. = P=(c )/(T)` ` THEREFORE PT=c =P(PV )/(NR )=C ` (From ideal gas equation`V+(nRT)/(P ) = nRTxx(T)/(C) therefore= dV=(nR )/(C ) xx 2TDelta T ` ` thereforeW= int PdV = (c )/(T )xx (2 nR )/( c ) xx TdT = 2 nR int_(T_0)^(2T) DT= 2n R xx T_0= W=4RT_0thereforeW= 8 RT_0`