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Two moles of a gas at 1 bar and 298 K are compressed at constant Temperature by use of a constant pressure of 5 bar. How much work is done on the gas ? If the compression is driven by a 100-kg mass, how far will it fall in the earth's gravitational field ? (g=9.8 ms^(-2)) |
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Answer» Solution :We have, for an irreversible ISOTHERMAL process, `W=-p_(2)(V_(2)-V_(1))` …(Eqn. 2) `=-p_(2)((nRT)/(p_(2))-(nRT)/(p_(1)))` `=nRT(1-(p_(2))/(p_(1)))` `-2xx8.314xx298 (1-(5)/(1))` `=19820 J`. Further, W=mgh …(Eqn. 3b) `H=(W)/(mg)=(19820)/(100xx9.8)m` `=20.22` m. The following problems are based on THERMOCHEMICAL CALCULATIONS. In dealing with these problems, we apply the INSPECTION method, as discussed previously. |
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