1.

Two moles of a gas at 1 bar and 298 K are compressed at constant Temperature by use of a constant pressure of 5 bar. How much work is done on the gas ? If the compression is driven by a 100-kg mass, how far will it fall in the earth's gravitational field ? (g=9.8 ms^(-2))

Answer»

Solution :We have, for an irreversible ISOTHERMAL process,
`W=-p_(2)(V_(2)-V_(1))` …(Eqn. 2)
`=-p_(2)((nRT)/(p_(2))-(nRT)/(p_(1)))`
`=nRT(1-(p_(2))/(p_(1)))`
`-2xx8.314xx298 (1-(5)/(1))`
`=19820 J`.
Further, W=mgh …(Eqn. 3b)
`H=(W)/(mg)=(19820)/(100xx9.8)m`
`=20.22` m.
The following problems are based on THERMOCHEMICAL CALCULATIONS. In dealing with these problems, we apply the INSPECTION method, as discussed previously.


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