Two moles of ammonia occupy a volume of 5 L at 27^@C and 9.32 atm pressure. Calculate the compressibility factor of the gas.

Two moles of ammonia occupy a volume of 5 L at 27^@C and 9.32 atm pres

1.	Two moles of ammonia occupy a volume of 5 L at 27^@C and 9.32 atm pressure. Calculate the compressibility factor of the gas.
Answer» Solution :In the PRESENT case, `P= 9.32" atm, " "" V=5L, ""T = 27 + 273 = 300 K` `n = 2, " and " "" R=0.0821 L " atm " K^(-1) mol^(-1)` The COMPRESSIBILITY factor Z is given by `Z=(PV)/(nRT)` `:. "" Z= (9.32xx5)/(2xx0.0821xx300) =0.946` Hence, the compressibility factor for NH3 under the given conditions is 0.946.