1.

Two moles of an ideal gas are allowed to expand from a volume of 10 dm^(3) to 2m^(3) at 300 K against a pressure of 101.325 kPa. Calculate the work done.

Answer»

<P>`-201.6` kJ
`13.22` kJ
`-810` J
`-18.96` kJ

Solution :`V_(1) = 10 DM^(3) = 10p^(-2) m^(3)`
`V_(2) = 2m^(3)`
P=`101.325 xx 10^(3)` Pa
`W= P DeltaV = -101. 325 xx 10^(3)(2-0.01)`
`=-201.6` kJ


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