Two moles of an ideal gas expand isothermally and reversibly from 1 litre to 10 litre at 300K, The enthalpy change (in kJ) for the processis

Two moles of an ideal gas expand isothermally and reversibly from 1 li

1.	Two moles of an ideal gas expand isothermally and reversibly from 1 litre to 10 litre at 300K, The enthalpy change (in kJ) for the processis
Answer» 11.4 kJ `-11.4kJ` `0 kJ` `4.8 kJ` Solution :`DeltaH =DELTA( U + PV) = DeltaU + Delta(RT) =DeltaU + R DeltaT` Forisothermal expansion of ideal gas, `DeltaU = 0` `( :' DeltaU =C_(v) DeltaT ` and `DeltaT =0)` `:. DeltaH =0 +0, i.e., DeltaH =0` or putting `DeltaU = C_(v) DeltaT , DeltaH = C_(v) DeltaT + R DeltaT` `= (C_9v) +R) DeltaT = C_(p) DeltaT` for 1 mole. For N moles, `DeltaH = n C_(p) DletaT =0`