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Two moles of an ideal gas goes under the process shown in figure. AB and CD are reversible adiabatic process. The efficiency of the cycle isA. `1//4`B. `1//2`C. `3//4`D. `3//5` |
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Answer» Correct Answer - C `Q_(DA) = nCP (T_(A) - T_(D))` `= 2 xx Cp ((P_(0) xx V_(0))/(2R) - (P_(0)v_(0))/(2R))` `= 2Cp ((P_(0)V_(0))/(2R))` `Q_(BC) = 2Cp ((P_(0))/(32) xx (8V_(0))/(2R) - (P_(0))/(32) xx (16V_(0))/(2R))` `= - 2Cp ((P_(0)V_(0))/(8R))` (Negative sign shows loss in heat) `eta = 1 - (Q_(BC))/(Q_(DA)) = (3)/(4)` |
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