Two moles of an ideal gas was heated isobarically so that its temperature was raised by 100 K. The heat absorbed during the process was 4000 J. Calculate (i) the work done by the gas, (ii) the increase in internal energy and (ii) the value of y for the gas [R =8.31 J mol ^(-1) K ^(-1) ].

Two moles of an ideal gas was heated isobarically so that its temperat

1.	Two moles of an ideal gas was heated isobarically so that its temperature was raised by 100 K. The heat absorbed during the process was 4000 J. Calculate (i) the work done by the gas, (ii) the increase in internal energy and (ii) the value of y for the gas [R =8.31 J mol ^(-1) K ^(-1) ].
Answer» Solution :`n = 2, Delta T = 100 K, Q = 4000 J` Work done by the GAS `= n R Delta T` `Delta W = 2 xx 8. 31 xx 100 = 1662 J` Increases in internal ENERGY `= Delta U = Q - Delta W` `= 4000 - 1662 = 2338 J` Also `Delta U = (R Delta T)/(gamma -1) = 2338` ` gamma -1 = (8. 31 xx 100)/(2338) = 0.35` `gamma = 1. 35`