1.

Two moles of an ideal monoatomic gas undergoes a cyclic process ABCA as shown in V-T diagram below: Work done by the gas during the entire cycle is :

Answer»

600R (1-ln2)
1200R
1200R(1-ln2)
Zero

Solution :For BC, VT=CONSTANT
or `PV^2`=constant (K=2 for polytropic PROCESS)
`:. W_(BC)=(nR)/(K-1)(T-T)=(2xxR)/(2-1)(1200-600)=1200R`
Work done by gas during ENTIRE cycle `=W_(AB)+W_(BC)+W_(CA)`
= - 1200 Rln2+1200 R+0 =1200 R(1-ln2)


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