1.

Two moles of n ideal gas are allowed to expand from a volume of 10dm^(3) to m^(3) at 300 K against a pressure of 101.325 kPa. Calculate the work done

Answer»

`-20.16kJ`
`13.22kJ`
`-810.6J`
`-18.96kJ`

Solution :Given, Number of moles (n)=2
Intial VOLUME `(V_(1))=10dm^(3)=0.01m^(3)`
`(because1dm^(3)=(1)/(1000)m^(3))`
Final volume `(V_(2))=2m^(3)`
`P_("ext")=101.325kPa`
Temperature (T) = 300k
`because` Work done due to CHARGE in volume against a CONSTANT pressure is given by
`W=-P_("ext")(V_(2)-V_(1))`
`:." "w=-101.325kPaxx(2-0.0.1)m^(3)`
`=-201.636kPam^(3)or-201.6kJ`
`(because1kJ=akPam^(3))`


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