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Two numbers 'a' and 'b' are selected successively without replacement in that order from the integers 1 to 10. The probability that a/b is an integer, isA. \(\frac{17}{45}\)B. \(\frac{1}{5}\)C. \(\frac{17}{90}\)D.\(\frac{8}{45}\) |
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Answer» Total numbers of elementary events are: 10 x 9 = 90 Being numbers are of non-replacing nature and order matters Let E be the event of a/b as an integer Favorable events are: \(\frac{2}1\), \(\frac{3}1\) , \(\frac{4}1\), \(\frac{4}2\), \(\frac{5}1\) , \(\frac{6}1\), \(\frac{6}2\), \(\frac{6}3\) , \(\frac{7}1\), \(\frac{8}4\), \(\frac{8}2\) , \(\frac{8}1\), \(\frac{9}3\) , \(\frac{9}1\) , \(\frac{10}5\), \(\frac{10}2\) , \(\frac{10}1\) Numbers of favorable outcomes are: \(\frac{17}{90}\) P (a/b is an integer) = P (E) = \(\frac{17}{90}\) |
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