Two oxides of a metal contain 27.6% and 30.0% of Oxygen, respecttively. If the formula of the first be M_(3) O_(4). Find that of the second.

Two oxides of a metal contain 27.6% and 30.0% of Oxygen, respecttively

1.	Two oxides of a metal contain 27.6% and 30.0% of Oxygen, respecttively. If the formula of the first be M_(3) O_(4). Find that of the second.
Answer» Solution :Suppose, the atomic weight of the metal is x. The OXIDE A has the molecular formula `M_3O_4`. The molecular mass of `A = 3x + 64.0` Hence, the percentage of oxygen in A `=64/(3x + 64) xx 100` According to the given data, A contains 27.60 % oxygen `therefore 64/(3x + 64) x 100 = 27.60` or `x = 55.96` THUS, the atomic weight of the metal M is 55.96. Formula of the oxide B can be obtained as FOLLOWS : Hence, the formula of oxide B `=M_(2)O_(3)`.