1.

Two oxides of a metal contain `50%` and `40%` metal `M` respectively. If the formula of the first oxide is `MO_(2)`, the formula of the second oxide will beA. (a)`MO_(2)`B. (b)`MO_(3)`C. (c )`M_(2)O`D. (d)`M_(2)O_(5)`

Answer» Correct Answer - B
`underset(50%)M underset(50%) (O_(2)) 50 g.......1 "metal" underset(40)(M_(x)) underset(60)(O_(y))`
`1 g…….(1)/(50) :. 40 g…….(4)/(5)` metal
and `50 g…….2 `oxygen
`1 g…….(2)/(50)` oxygen
For second oxide Atoms of metal
`(M)=(1xx40)/50=0.8` similarly
Atoms of oxygen`=(2xx60)/50=12/5=2.4`
Hence, ratio of `M:O=0.8:2.4` or `1:3`
`:.` Formula of the same metal oxide is `MO_(3)`


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