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Two oxides of a metal contain `50%` and `40%` metal `M` respectively. If the formula of the first oxide is `MO_(2)`, the formula of the second oxide will beA. (a)`MO_(2)`B. (b)`MO_(3)`C. (c )`M_(2)O`D. (d)`M_(2)O_(5)` |
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Answer» Correct Answer - B `underset(50%)M underset(50%) (O_(2)) 50 g.......1 "metal" underset(40)(M_(x)) underset(60)(O_(y))` `1 g…….(1)/(50) :. 40 g…….(4)/(5)` metal and `50 g…….2 `oxygen `1 g…….(2)/(50)` oxygen For second oxide Atoms of metal `(M)=(1xx40)/50=0.8` similarly Atoms of oxygen`=(2xx60)/50=12/5=2.4` Hence, ratio of `M:O=0.8:2.4` or `1:3` `:.` Formula of the same metal oxide is `MO_(3)` |
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