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Two parallel chords are drawn in a circle ofdiameter 30.0 cm. The length of one chord is24.0 cm and the distance between the twochords is 21.0 cm; find the length of the otherchord. |
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Answer» Let the first chord=24 cmSecond chord=x cmRadius=Diameter/2 =30cm/2 =15cm Note that half of first chord,half of second chord and the radius form a right angle triangle with the radius as the hypotenuse Using Pythagorean theorem[Half of first chord]^2+[Half of second chord]^2=Radius^212^2+[Half of second chord]^2=15^2144+[Half of second chord]^2=225[Half of second chord]^2=225-144[Half of second chord]^2=121[Half of second chord] =121^(1/2)[Half of second chord] =11 So Answer Is 11 cm. |
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