Two parallel forces of 4000 N are applied tangentially in opposite direction to the opposite faces of a metallic cube of side length 0.25 m. The shear modulus of the material is `80xx10^(9)` Pa. Then the displacement of the upper surface relative to the lower surface isA. `2xx10^(-5)m `B. `2xx10^(-6)m `C. `2xx10^(-7)m`D. `2xx10^(-8)m `

Two parallel forces of 4000 N are applied tangentially in opposite dir

1.	Two parallel forces of 4000 N are applied tangentially in opposite direction to the opposite faces of a metallic cube of side length 0.25 m. The shear modulus of the material is `80xx10^(9)` Pa. Then the displacement of the upper surface relative to the lower surface isA. `2xx10^(-5)m `B. `2xx10^(-6)m `C. `2xx10^(-7)m`D. `2xx10^(-8)m `
Answer» Correct Answer - C `x=(Fh)/(A eta) = (4000 xx 0.25)/(625xx10^(-4) xx 80xx10^(9)) = 2xx10^(-7)m.`

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