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Two parallel plate air capacitors have their plate areas `100 and 500 cm^(2)` respectively. If they have the same charge and potential and the distance between the plates of the first capacitor of 0.5 mm, what is the distance between the plates of second capacitor ? |
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Answer» Here, two parallel plate capaictors have same charge q and same potential V, so they have equal capacitances as `C = q//V`, `C_(1) = C_(2)` `(in_(0) A_(1))/(d_(1)) = (in_(0) A_(2))/(d_(2))` or `d_(2) = (A_(2))/(A_(1))d_(1)` Now `A_(1) = 100 cm^(2), A_(2) = 500 cm^(2)`, `d_(1) = 0.5 mm = 0.5cm` `:. d_(2) = (500xx0.05)/(100) = 0.25 cm = 2.5 mm` |
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