Two parallel plates, each of area A = 1m^2 are separated by a distance g. The electric field intensity between the plates is 3∗10^6 v/m. What is the force between the two plates?(a) 1/2π∗10^3 N(b) 1/8π∗10^3 N(c) 8π∗10^3 N(d) 0 NThis question was posed to me by my college professor while I was bunking the class.The origin of the question is Singly Excited Electric Field Systems in division Basic Concepts in Rotating Machines of Electrical Machines

Two parallel plates, each of area A = 1m^2 are separated by a distance

1.	Two parallel plates, each of area A = 1m^2 are separated by a distance g. The electric field intensity between the plates is 3∗10^6 v/m. What is the force between the two plates?(a) 1/2π∗10^3 N(b) 1/8π∗10^3 N(c) 8π∗10^3 N(d) 0 NThis question was posed to me by my college professor while I was bunking the class.The origin of the question is Singly Excited Electric Field Systems in division Basic Concepts in Rotating Machines of Electrical Machines
Answer» The correct choice is (b) 1/8π∗10^3 N The best I can EXPLAIN: When electric field is applied, the plates MOVE towards each other because of force of attraction by a distance X ⇒ C = ε0A/(g-x) Wfld(q,x) = 1/2 q^2/C = 1/2 q^2(g-x)/Aε0 fe = -∂Wfld(q,x)/∂x = 1/2q^2x/Aε0 We KNOW, q = DA = ε0EA and ε0 = 10^-9/36Π fe = 1/2 E^2ε0A = 1/2∗(3∗10^6)^2∗10^-9/36Π∗1 = 1/8π∗10^3 N

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