1.

Two particle A and B, move with constant velocities vec(v_1) and vec(v_2). At the initial moment their position vectors are vec(r_1) and vec(r_2) respectively . The condition for particles A and B for their collision is

Answer»

`vec(r_1) XX vec(v_1) = vec(r_2) xx vec(v_2)`
`vec(r_1) - vec(r_2)= vec(v_1)- vec(v_2)`
`(vec(r_1) - vec(r_2))/(|vec(r_1) - vec(r_2)|) = (vec(v_2) - vec(v_1))/(|vec(v_2)- vec(v_1)|)`
`vec(r_1). vec(v_1) = vec(r_2) . vec(v_2)`

Solution :Let the PARTICLES A and B collide at TIME t. For their collision, the position VECTORS of both particles should be same at time t, i.e.
`vec(r_1) + vec(v_1) t = vec(r_2) + vec(v_2)t`
`vec(r_1) - vec(r_2) = vec(v_2) t = (vec(v_2) - vec(v_1)) t`
Also, `|vec(r_1) - vec(r_2)| = |vec(v_2) - vec(v_1)|t " or " t = (|vec(r_1) - vec(r_2)|)/(|vec(v_2) - vec(v_1)|)`
Substituting this value of t in eqn. (i), we get
`vec(r_1) - vec(r_2) = (vec(v_2) - vec(v_1)) (|vec(r_1) - vec(r_2)|)/(|vec(v_2) - vec(v_1)|) " or " (vec(r_1) - vec(r_2))/(|vec(r_1)-vec(r_2)|) = ((vec(v_2) - vec(v_1)))/(|vec(v_2) -vec(v_1)|)` .


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