1.

Two particle of masses m_(1).m_(2) moves with initial velocities u_(1) and u_(2) . On collision one of the particles get excited to higher level afterabsorbingenergy epsilon .If final velocitiesofparticles be v_(1) and v_(2) then we must have :

Answer»

`1/2m_(1)u_(1)^(2) +1/2 m_(2)u_(2)^(2) =1/2m_(1)v_(1)^(2)+1/2m_(2)v_(2)^(2)-epsilon`
`1/2 m_(1)u_(1)^(2) +1/2m_(2)u_(2)^(2) - epsilon =1/2 m_(1)v_(1)^(2) +1/2m_(2)v_(2)^(2)`
`1/2m_(1)^(2)u_(1)^(2)+1/2m_(2)^(2)u_(2)^(2)+epsilon =1/2 m_(1)^(2)v_(1)^(2)+1/2m_(2)^(2)v_(2)^(2)`
`m_(1)^(2)u_(1)+m_(2)^(2)u_(2)-epilon=m_(1)^(2)v_(1)+m_(2)^(2)v_(2)`

Solution :Energy is always be CONSERVED so
`K.E_("INTIAL")=K.E_("FINAL") +` Excitation energy
`1/2 m_(1)u_(1)^(2)+1/2m_(2)u_(2)^(2)-epsilon =1/2m_(1)v_(1)^(2)+1/2m_(2)v_(2)^(2)`


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