1.

Two particles A and B are in motion. If the wavelength associated with particle A is `5 xx 10^(-8)m`, calculate the wavelength associated with particle B if its monentum is half of A

Answer» By de Broglie equation, `lamda_(A) = (h)/(p_(A)) and lamda = (h)/(p_(B))`
`:. (lamda_(A))/(lamda_(B)) = (p_(B))/(p_(A))`
But `p_(B) = (1)/(2) p_(A)` (Given)
`:. (lamda_(A))/(lamda_(B)) = (1//2p_(A))/(p_(A)) = (1)/(2) or lamda_(B) = 2xx lamda_(A) = 2 xx 5 xx 10^(-8) m = 10^(-7)m`


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