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Two particles A and B are in motion. If the wavelength associated with particle A is `5 xx 10^(-8)m`, calculate the wavelength associated with particle B if its monentum is half of A |
Answer» By de Broglie equation, `lamda_(A) = (h)/(p_(A)) and lamda = (h)/(p_(B))` `:. (lamda_(A))/(lamda_(B)) = (p_(B))/(p_(A))` But `p_(B) = (1)/(2) p_(A)` (Given) `:. (lamda_(A))/(lamda_(B)) = (1//2p_(A))/(p_(A)) = (1)/(2) or lamda_(B) = 2xx lamda_(A) = 2 xx 5 xx 10^(-8) m = 10^(-7)m` |
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