InterviewSolution
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InterviewSolution
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Two particles are projected in air with speed `v_(0)` at angles `theta_(1)` and `theta_(2)` (both acute) to the horizontal,respectively.If the height reached by the first particle greater than that of the second,then thick the right choicesA. angle of projection:`theta_(1)gt theta_(2)`B. time of flight:`T_(2) gt T_(1)`C. horizontal range:`R_(1) gt R_(2)`D. total energy : `U_(1) gt U_(2)` |
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Answer» Correct Answer - A::B::C `H_(1)gtH_(2)` `sin theta_(1)-sin theta_(2)` or `theta_(1)gttheta_(2)` `T_(1)gtT_(2)` `R_(1)/R_(2)=(sin 2theta_(1))/(sin 2theta_(2))gt1` `U_(1)=KE+PE=1/2m_(1)v_(0)^(2)` `U_(2)=KE+PE=1/2m_(2)v_(0)^(2)` If `m_(1)=m_(2)` then `U_(1)=U_(2)` `m_(1)gtm_(2)` then `U_(1)gtU_(2)` `m_(1)ltm_(2)` then `U_(1)ltU_(2)` |
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