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Two particles are projected simultaneously with the same speed `v` in the same vertical plane with angles of elevation `theta`, and `2theta`, where `theta lt 45^(@)`.At what time will velocities be parallel?A. `t=v/(g) "tan"theta/2 "cosec"(3theta)/2`B. `t=v/(g) "cos"theta/2 "cot"(3theta)/2`C. `t=v/(g)"cos"theta/2 "tan"(3theta)/2`D. `t=v/(g) "cos" theta/2 "cosec"(3theta)/2` |
Answer» Correct Answer - D Velocity of particle after time `t` is `vecV_(1)=(v cos theta hati+v sin theta hatj)-(ghatj)t` `vecV_(2)=(v cos 2theta hati+v sin 2theta hatj)-(ghatj)t` To be parallel of `V_(1)` and `V_(2)` `rArr (v cos theta)/(v cos 2theta)=(v sin theta-"gt")/(v sin 2theta-"gt")` Solving the above equation, we get, `t=v/gcos(theta/2)cosec(3theta)/2` |
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