InterviewSolution
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InterviewSolution
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Two particles, each of mass m are attached to the two ends of a light string of length l which passes through a hole at the centre of a table. One particle describes a circle on the table with angular velocity `omega_(1)` and the other describes a circle as a conical pendulum with angular velocity `omega_(2)` below the table as shown in figure -3.86. if `l_(1)` and `l_(2)` are the lengths of the portion of the string above and below the table then : A. `l_(1)/l_(2)=(omega_(2)^(2))/(omega_(1)^(2))`B. `l_(1)/l_(2)=(omega_(1)^(2))/(omega_(2)^(2))`C. `1/(omega_(1)^(2))+1/(omega_(2)^(2)=l/g`D. `1/(omega_(1)^(2))+1/(omega_(2)^(2)) gt l/g` |
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Answer» Correct Answer - A |
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