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Two particles each of mass m are placed at points P and Q . R is the mid point of PQ = l . The gravitational force on the third particle of mass m placed at point s on the perpendicular bisector of PQ at a distance l from R is ?A)Gm2/l2B)16Gm2/5l2C)16Gm2/5(5)1/2l22D)4(2)1/2Gm2/5l2 |
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Answer» Fnet = 2 F cos theta Fnet = 4 * 2 * Gm2/5l2 * 2l/l51/2 Fnet = 16Gm2/53/2l2 |
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