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Two particles having charges Q_(1) and Q_(2) , when kept at a certain distance, exert a force F on each other. If the distance between the two particles is reduced to half and the charge on each particle is doubled. Find the force between the particles. |
| Answer» <html><body><p></p>Solution :`<a href="https://interviewquestions.tuteehub.com/tag/f-455800" style="font-weight:bold;" target="_blank" title="Click to know more about F">F</a> = (1)/(4 <a href="https://interviewquestions.tuteehub.com/tag/pi-600185" style="font-weight:bold;" target="_blank" title="Click to know more about PI">PI</a> epsilon_(0)) (Q_(1)Q_(2))/(<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>^(2))` <br/> If the distance is <a href="https://interviewquestions.tuteehub.com/tag/educed-7679860" style="font-weight:bold;" target="_blank" title="Click to know more about EDUCED">EDUCED</a> byhalf and two particles of charges are doubled. <br/> F. = `(1)/(4pi epsilon_(0)) (2Q_(1)2Q_(2))/((r//2)^(2)) = (1)/(4pi epsilon_(0)) (4Q_(1)Q_(2))/((r^(2)//4)^(2))` <br/> `F. = (1)/(4pi epsilon_(0)) (16(Q_(1)Q_(2)))/(r^(2)) = 16 [ (1)/(4pi epsilon_(0)) (Q_(1)Q_(2))/(r^(2))]` <br/> F. = 16 F</body></html> | |